0=(4y-y^2)/(y^2-4)

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Solution for 0=(4y-y^2)/(y^2-4) equation: 


D( y )

y^2-4 = 0

y^2-4 = 0

y^2-4 = 0

1*y^2 = 4 // : 1

y^2 = 4

y^2 = 4 // ^ 1/2

abs(y) = 2

y = 2 or y = -2

y in (-oo:-2) U (-2:2) U (2:+oo)

0 = (4*y-y^2)/(y^2-4) // - (4*y-y^2)/(y^2-4)

0-((4*y-y^2)/(y^2-4)) = 0

-((4*y-y^2)/(y^2-4)) = 0

(-1*(4*y-y^2))/(y^2-4) = 0

4*y-y^2 = 0

y*(4-y) = 0

4-y = 0 // - 4

-y = -4 // * -1

y = 4

y*(y-4) = 0

(-1*y*(y-4))/(y^2-4) = 0

( y-4 )

y-4 = 0 // + 4

y = 4

( y )

y = 0

y in { 4, 0 }

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